When a small object is released from the top of a skyscraper, it takes the object 9 secs to hit the ground. Given this information, what can you say about the height of the skyscraper?

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Quizplus · Accepted Answer

The basic equation for total distance traveled is: d= (V_initital)(t) + (0.5)a(t²) d = displacement of the object (distance traveled) V_initial = initial velocity t = time a = acceleration Step 1: Determine the information from the word problem you can plug into the equation. d = unknown (this is what we are solving for) t = 9 seconds a = 9.8 m/s² The object in this scenario is falling, so the acting force is gravity. The acceleration for any object moving under the sole influence of gravity (i.e. hanging from a spring) is the gravitational constant which is 9.8 m/s² so the equation is now: V = 0 Since the object starts from rest, the initial velocity is 0. Step 2: Solve for the distance traveled. 11ec0fda_997d_5e8e_a67f_01cc96e4a722_NR0004_00 11ec0fda_997d_5e8f_a67f_5f96c792c431_NR0004_00

When a Small Object Is Released from the Top of a Skyscraper