A 45 kg bowling ball rolling at 0.75 m/s strikes a stationary 2.5 kg bowling pin and knocks it back with a velocity of 1.5 m/s. How fast will the bowling ball be moving?

Question

Quizplus · Accepted Answer

To calculate the momentum of a two-body problem, use the following equation: m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂' Once you plug in the values from the word problem, you would have: (45 kg)(0.75 m/s) + (2.5 kg)(0 m/s) = (45 kg)v1' + (2.5 kg)(1.5 m/s) 33.75 kg m/s + 0 m/s = (45 kg)v1' + 3.75 kg m/s 30 kg m/s = (45 kg)v1' v1' = (30 kg m/s) / (45 kg) v1' = 0.67 m/s

A 45 Kg Bowling Ball Rolling at 0