If a spring is being stretched 150 cm with a force of 20 N, how far will it stretch if the force is increased to 7 N?

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Quizplus · Accepted Answer

The spring has the same spring constant regardless of the force applied to it. The spring constant can then be used to determine the stretch of the spring given any applied force. The spring constant and displacement are determined by the equation k = f/x, where: k is the spring constant, measured in Newtons per meter (N/m) f is the force, measured in Newtons, applied to the spring x is the distance of displacement from equilibrium, measured in meters Step 1: Determine the values provided in the problem and convert units to match the units used in the standard equations. Remember, we are measuring: f (force) in Newtons (N) x (distance of displacement from equilibrium) in meters (m) m (mass of object) in kilograms (kg) a (acceleration of object) in meters per second squared (m/s²⁾ The word problem provides information using centimeters, which need to be converted to meters. Distance from equilibrium = 150 cm = 1.5 m Step 2: Calculate the spring constant based on the stretch (displacement) of the spring at a force of 20N. k = f / x k = 20 N / 1.5 m k= 13.3 N / m. Step 3: Calculate the displacement of the spring based on the increased force of 7N. k = f/x x = f/k x = 7 N / (13.3 N / m) x = 0.52 m = 52 cm

If a Spring Is Being Stretched 150 Cm with a Force