Two point-like charges carrying charges of + 0.5 μC and - 0.4 μC are 2 m apart. Determine the magnitude of the force between them.

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To find the magnitude of the resulting force between the two objects, use Coulomb's Law: 11ec0fda_9984_b1ad_a67f_8dde1efa77cd_NR0004_00 Q1 = the charge on the point-like object one (unit of measure is Coulomb, C) Q2 = the charge on the point-like object two (unit of measure is Coulomb,C ) r = the distance between the two objects (unit of measure is meter, m) k = the proportionality constant (unit of measure is N.m²c²) 11ec0fda_9984_b1ae_a67f_7783ff58ef53_NR0004_00 Step 1: Convert μC to C (1 μC = 1 x 10^-6 C) +0.5 μC = 5 x 10^-6 C - 0.4 μC = 4 x 10^-6 C Step 2: Insert the values into the equation Q1 = 5 x 10^-6 C Q2 = 4 x 10^-6 C r = 2 11ec0fda_9984_b1af_a67f_89a6bd8eb4f6_NR0004_00 The magnitude of the force is F = 45x 10^-5N The minus sign is a result of the two point charges having opposite signs; therefore, the electrostatic force is attractive

Two Point-Like Charges Carrying Charges of + 0