A baseball is thrown with the speed of 30 m/s horizontally from the window of a train traveling with a speed of 40 m/s. The height of the pitcher's hand form the land while throwing the ball was 4.9 m. If there is no air resistance, how far out from the train will the ball land?

Question

Quizplus · Accepted Answer

This problem provides the vertical distance (height of the pitcher's hand), vertical acceleration (gravitational constant), and the initial horizontal velocity (speed of the ball). V_x = Horizontal velocity (30 m/s) d_y = vertical displacement of the object (4.9 m) d_x = unknown (this is what we are solving for) t = unknown (flight time) a = gravitational constant (9.8 m/s²) Since we assume there is no air resistance, d_h = V_x t. We solve this problem in two steps. Step 1: Calculate flight time Flight Time = √((vertical distance)/(1/2)(vertical acceleration)) Flight Time = √((4.9 m)/(1/2)(9.8 m/s²)) Flight Time = 1 s Step 2: Use the horizontal distance equation to solve for horizontal distance d_x = vxt d_x = 30 m/s × 1 s d_x = 30 m Since there is no air resistance, the baseball will land 30 m from the train.

A Baseball Is Thrown with the Speed of 30 M/s