A 200 g stone attached to a string is rotated about a 2 meter radius. If the string broke when it was at 18 N of tension, how fast was the ball moving?

Question

Quizplus · Accepted Answer

In this question, we use the formula for the centripetal acceleration;
 11ec0fda_9989_93be_a67f_d1b30bf17300_NR0004_00 a = centripetal acceleration
V = velocity
r = radius of the circular path
STEP 1. Since acceleration is not given, we find it out by using Newton's second law of motion equation;
F = ma
Filling in the values:
 11ec0fda_9989_93bf_a67f_052c8766ef1f_NR0004_00 STEP 2. Then, we use the formula for the centripetal acceleration to find out the velocity of the ball.
 11ec0fda_9989_93c0_a67f_c793c2022ddd_NR0004_00 a = centripetal acceleration
V = velocity
r = radius of the circular path
Convert the equation:
 11ec0fda_9989_93c1_a67f_13a6759818db_NR0004_00 Fill in the values:
 11ec0fda_9989_93c2_a67f_0db49abece42_NR0004_00

A 200 G Stone Attached to a String Is Rotated