A New Caledonian Crow releases a nut from a height of 78m to collect the meat once it breaks. In 4 seconds, the nut travels 78m before hitting the ground. What is the distance the nut travels in the last 2 seconds of its free fall?

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The basic formula for total distance traveled is 11ec0fda_998c_ef32_a67f_e559ef2fb0c6_NR0004_00 d = displacement of the object (distance traveled) t = time a = acceleration Here V(2)and V(4)represent the velocity at 2 seconds and 4 seconds, respectively. And the velocity V(t) at t seconds is 11ec0fda_998c_ef33_a67f_5388d945d592_NR0004_00 Step 1: Determine the information from the word problem you can plug into the equation. d = unknown (this is what we are solving for) t = 2 seconds (remember that it asks for the distance in the last 2 seconds) a = 9.8 m/s² The object in this scenario is falling, so the acting force is gravity. The acceleration for any object moving under the sole influence of gravity (i.e. hanging from a spring) is the gravitational constant which is 9.8 m/s² 11ec0fda_998c_ef34_a67f_bf5ceed2effa_NR0004_00

A New Caledonian Crow Releases a Nut from a Height