On a test with a population mean of 75 and standard deviation equal to 16, if the scores are normally distributed, what percentage of scores fall below a score of 83.8?
A) 55.00
B) 79.12
C) 20.88
D) 29.12
E) 70.88

Question

Quizplus · Accepted Answer

To find the percentage of scores below 83.8, calculate the z-score: z = (83.8 - 75) / 16 = 0.55. Using the standard normal distribution table, a z-score of 0.55 corresponds to approximately 70.88% of scores falling below this value.

On a Test with a Population Mean of 75 and Standard