Assume that the formula $h = h _ { 0 } - \frac { 1 } { 2 } g t ^ { 2 }$ holds true. Let g = 32.2 feet per second squared. Suppose a drop of water starts at the top of the falls and descends 130 feet. How long will it take the drop to reach halfway? How long will it take the drop to reach the bottom? Please round answers to the nearest tenth.
A) 2.4 sec; 3.2 sec
B) 2.2 sec; 3.0 sec
C) 2.0 sec; 3.0 sec
D) 2.2 sec; 2.8 sec
E) 2.0 sec; 2.8 sec

Question

Quizplus · Accepted Answer

To find the time it takes for the drop to reach halfway (65 feet), we use the formula with $h_0 = 130$ and $h = 65$, solving for $t$. Plugging in the values, we get $65 = 130 - \frac{1}{2} \cdot 32.2 \cdot t^2$, which simplifies to $32.2t^2 = 130 - 65$, and further to $32.2t^2 = 65$. Solving for $t$ gives approximately 2.0 seconds. To find the time to reach the bottom, we set $h = 0$, resulting in $0 = 130 - \frac{1}{2} \cdot 32.2 \cdot t^2$, which simplifies to $32.2t^2 = 130$. Solving for $t$ gives approximately 2.8 seconds.

Assume That the Formula h=h0−12gt2h = h _ { 0 } - \frac { 1 } { 2 } g t ^ { 2 }h=h0​−21​gt2

Assume That the Formula $h = h _ { 0 } - \frac { 1 } { 2 } g t ^ { 2 }$