public static int exampleRecursion (int n)
{
If (n == 0)
Return 0;
Else
Return exampleRecursion(n - 1) + n * n * n;
}Which of the following is an invalid call to the method in the accompanying figure?
A) exampleRecursion(-1)
B) exampleRecursion( 0)
C) exampleRecursion(1)
D) exampleRecursion(999)

Question

Quizplus · Accepted Answer

The method checks if n is equal to 0 before performing any computation. Since there is no way to have a negative value of n and still satisfy the base case (n == 0), calling the method with a negative value of n will result in an infinite recursion loop, which will eventually cause a stack overflow error. Therefore, option A is an invalid call to the method.

Public Static Int ExampleRecursion (Int N)