Factor the polynomial. $$9 z ^ { 2 } - 78 z + 169$$
A) $3 ( z + 13 ) ^ { 2 }$
B) $( 3 z + 13 ) ^ { 2 }$
C) $3 ( 13 - z ) ^ { 2 }$
D) $( 3 z - 13 ) ^ { 2 }$
E) $3 ( z - 13 ) ^ { 2 }$

Question

Quizplus · Accepted Answer

The polynomial can be rewritten as $(3z)^2 - 2 \cdot 3z \cdot 13 + 13^2$, which is the perfect square trinomial formula $(a - b)^2 = a^2 - 2ab + b^2$, where $a = 3z$ and $b = 13$. Therefore, the factored form is $(3z - 13)^2$.

Factor the Polynomial 9z2−78z+1699 z ^ { 2 } - 78 z + 1699z2−78z+169

Factor the Polynomial $9 z ^ { 2 } - 78 z + 169$