Solve the equation: $p ( 9 p + 2 ) = 0$
A) $0 , - \frac { 2 } { 9 }$
B) $0 , - 2$
C) $- 1,2$
D) $1 , - \frac { 2 } { 9 }$

Question

Quizplus · Accepted Answer

This is a quadratic equation in the form of $ax^2+bx+c=0$, where $a=9$, $b=2$, and $c=0$. Use the zero product property to solve: 
$$p(9p+2) = 0 \quad \Rightarrow \quad p=0 \textrm{ or } 9p+2=0 \quad \Rightarrow \quad p=0 \textrm{ or } p=-\frac{2}{9}$$
Thus, the solution set is $\{0, -\frac{2}{9}\}$, which is the same as choice A.

Solve the Equation p(9p+2)=0p ( 9 p + 2 ) = 0p(9p+2)=0

Solve the Equation $p ( 9 p + 2 ) = 0$