Find the area of the isosceles triangle shown in the illustration, where a = 11 and b = 10.

Question

Quizplus · Accepted Answer

First, we can use the Pythagorean theorem to find the length of the altitude from the vertex of the isosceles triangle to the base:

$h = \sqrt{a^2 - (\frac{b}{2})^2} = \sqrt{11^2 - 5^2} = \sqrt{96}$

Then, we can use the formula for the area of a triangle:

$A = \frac{1}{2}bh = \frac{1}{2} \cdot 10 \cdot \sqrt{96} = 5 \sqrt{96} \mathrm{in}^2$

Therefore, the answer is choice A.

Find the Area of the Isosceles Triangle Shown in the Illustration