Solve the equation. $4 y ^ { \frac { 1 } { 3 } } = 5$
A) $y = \frac { 125 } { 64 }$
B) $y = \frac { 5 } { 4 }$
C) $y = \frac { 125 } { 64 }$.
D) $y = - \frac { 5 } { 4 }$
E)no solution

Name: Solve the equation. $4 y ^ { \frac { 1 } { 3 } } = 5$ A) $y = \frac { 125 } { 64 }$ B) $y = \frac { 5 } { 4 }$ C) $y = \frac { 125 } { 64 }$. D) $y = - \frac { 5 } { 4 }$ E)no solution
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Question

Quizplus · Accepted Answer

Cube both sides of the equation to get rid of the radical:$$(4y^{1/3})^3 = 5^3$$$$64y = 125$$$$y = \frac{125}{64}$$

Solve the Equation 4y13=54 y ^ { \frac { 1 } { 3 } } = 54y31​=5

Solve the Equation $4 y ^ { \frac { 1 } { 3 } } = 5$