Find the center and radius of a circle given an equation in standard form.

Question

Quizplus · Accepted Answer

The equation is already in standard form, which is of the form $(x-a)^2+(y-b)^2=r^2$, where $(a,b)$ is the center and $r$ is the radius.
Comparing this to the given equation, we have:
$(x-0)^2 + (y-0)^2 = 11ec1e8e_2bcd_a77d_be9b_41a328ca6e31_TBX8967_11$
So the center is at $(0,0)$ and the radius is $\sqrt{11ec1e8e_2bcd_a77d_be9b_41a328ca6e31_TBX8967_11}$. 
Since none of the other answer choices match this, the answer is B.

Find the Center and Radius of a Circle Given an Equation