Find the sine, cosine, and tangent for the angle $A$ where a = 5 and b = 12.
A) $\sin A = \frac { 5 } { 13 }$ $\cos A = \frac { 12 } { 13 }$ $\tan A = \frac { 5 } { 12 }$
B) $\sin A = \frac { 5 } { 13 }$ $\cos A = \frac { 13 } { 12 }$ $\tan A = \frac { 5 } { 12 }$
C) $\sin A = \frac { 13 } { 5 }$ $\cos A = \frac { 12 } { 13 }$ $\tan A = \frac { 5 } { 12 }$
D) $\sin A = \frac { 12 } { 13 }$ $\cos A = \frac { 5 } { 13 }$ $\tan A = \frac { 5 } { 12 }$
E) $\sin A = \frac { 5 } { 13 }$ $\cos A = \frac { 12 } { 13 }$ $\tan A = \frac { 12 } { 5 }$

Question

Find the sine, cosine, and tangent for the angle $A$ where a = 5 and b = 12. 
A) $\sin A = \frac { 5 } { 13 }$ $\cos A = \frac { 12 } { 13 }$ $\tan A = \frac { 5 } { 12 }$ 
B) $\sin A = \frac { 5 } { 13 }$ $\cos A = \frac { 13 } { 12 }$ $\tan A = \frac { 5 } { 12 }$ 
C) $\sin A = \frac { 13 } { 5 }$ $\cos A = \frac { 12 } { 13 }$ $\tan A = \frac { 5 } { 12 }$ 
D) $\sin A = \frac { 12 } { 13 }$ $\cos A = \frac { 5 } { 13 }$ $\tan A = \frac { 5 } { 12 }$ 
E) $\sin A = \frac { 5 } { 13 }$ $\cos A = \frac { 12 } { 13 }$ $\tan A = \frac { 12 } { 5 }$

Quizplus · Accepted Answer

We have a right triangle with sides of length 5, 12, and 13 (considering the Pythagorean triple (5, 12, 13)).

The sine of angle A is opposite/hypotenuse, which is 5/13.
The cosine of angle A is adjacent/hypotenuse, which is 12/13.
The tangent of angle A is opposite/adjacent, which is 5/12.

Therefore, the answer is A.

Find the Sine, Cosine, and Tangent for the Angle AAA Where a = 5 and B = 12

Find the Sine, Cosine, and Tangent for the Angle $A$ Where a = 5 and B = 12