Consider the sets. $A =$ {four} $B =$ $\{ s , l , i , p \}$ $\mathrm { C } =$ {letters in the word bush } $D =$ $\{ 3 + 1 \}$ $E =$ {5} $F =$ {4} What is the cardinality of each set?
A) $| A | = 3$ ; $| B | = 1$ ; $| C | = 1$ ; $| D | = 1$ ; $| E | = 1$ ; $| F | = 1$ ;
B) $| A | = 1$ ; $| B | = 4$ ; $| C | = 4$ ; $| D | = 1$ ; $| E | = 1$ ; $| F | = 1$ ;
C) $| A | = 1$ ; $| B | = 4$ ; $| C | = 3$ ; $| D | = 3$ ; $| E | = 1$ ; $| F | = 1$ ;
D) $| A | = 1$ ; $| B | = 3$ ; $| C | = 3$ ; $| D | = 1$ ; $| E | = 1$ ; $| F | = 3$ ;
E) $| A | = 4$ ; $| B | = 1$ ; $| C | = 1$ ; $| D | = 1$ ; $| E | = 4$ ; $| F | = 1$ ;

Question

Quizplus · Accepted Answer

- |A| = 1, as there is only one element in set A, which is "four".
- |B| = 4, as there are four elements in set B, which are "s", "l", "i", and "p".
- |C| = 4, as the word "bush" has four distinct letters.
- |D| = 1, as the set D only has one element, which is 4 (since 3+1=4).
- |E| = 1, as the set E only has one element, which is 5.
- |F| = 1, as the set F only has one element, which is 4.

Consider the Sets A=A =A= {Four} B=B =B= {s,l,i,p}\{ s , l , i , p \}{s,l,i,p}

Consider the Sets $A =$ {Four} $B =$ $\{ s , l , i , p \}$