Find the probability of the event with odds in favor of 6 to 7.
A) $P ( E ) = \frac { 7 } { 6 }$
B) $P ( E ) = \frac { 6 } { 13 }$
C) $P ( E ) = \frac { 7 } { 13 }$
D) $P ( E ) = \frac { 6 } { 7 }$
E) $P ( E ) = \frac { 1 } { 7 }$

Question

Quizplus · Accepted Answer

Odds in favor of 6 to 7 means that for every 6 favorable outcomes, there are 7 unfavorable outcomes. The total number of outcomes is 6+7=13. Therefore, the probability of a favorable outcome is 6/13.

Find the Probability of the Event with Odds in Favor P(E)=76P ( E ) = \frac { 7 } { 6 }P(E)=67​

Find the Probability of the Event with Odds in Favor $P ( E ) = \frac { 7 } { 6 }$