Consider the following test scores obtained by a class: $\text { cellpadding }=" 0 \text { " cellspacing }=" 0 " \text { width }=52 \% " \text { border="0" }$

$$\begin{array} { l l }
\text { Test Score } & \text { Frequency } \
90 & 1 \
80 & 2 \
70 & 10 \
60 & 5 \
50 & 2
\end{array}$$ Find the range and mean, rounded to the nearest unit.
A) range: $40$ mean: $4$
B) range: $270$ mean: $68$
C) range: $68$ mean: $40$
D) range: $50$ mean: $70$
E) range: $40$ mean: $68$

Question

Consider the following test scores obtained by a class: $\text { cellpadding }=" 0 \text { " cellspacing }=" 0 " \text { width }=52 \% " \text { border="0"> }$

$$\begin{array} { l l } 
\text { Test Score } & \text { Frequency } \
90 & 1 \
80 & 2 \
70 & 10 \
60 & 5 \
50 & 2
\end{array}$$ Find the range and mean, rounded to the nearest unit.
A) range: $40$ mean: $4$
B) range: $270$ mean: $68$
C) range: $68$ mean: $40$
D) range: $50$ mean: $70$
E) range: $40$ mean: $68$

Quizplus · Accepted Answer

The range is the difference between the highest and lowest scores, which is $90 - 50 = 40$. To find the mean, multiply each test score by its frequency, add these products, and then divide by the total number of scores. The calculation is $\frac{(90*1)+(80*2)+(70*10)+(60*5)+(50*2)}{1+2+10+5+2} = \frac{900}{20} = 45$. However, there was a mistake in my calculation; correctly, it should be $\frac{(90*1)+(80*2)+(70*10)+(60*5)+(50*2)}{1+2+10+5+2} = \frac{1350}{20} = 67.5$, which rounds to $68$.

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