The genes F and G act in accordance with the Dobzhansky-Muller model leading to sterility in hybrids between two species of monkeyflowers.Any combination of the F1 and the G2 alleles causes hybrids to be sterile.Based on the Dobzhansky-Muller model, which genotype should have high fitness?

Question

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According to the Dobzhansky-Muller model, hybrid sterility occurs when incompatibilities arise between two or more genes that have diverged in the two species since their last common ancestor. In this case, the F and G genes act in accordance with this model and any combination of F1 and G2 alleles lead to sterility. Therefore, the genotype that would have high fitness in this scenario would be the one that has both F1 and G1 without the presence of the incompatible G2 allele. Therefore, option A) F1F1; G1G1, would have high fitness as it carries the compatible alleles for both F and G genes.

The Genes F and G Act in Accordance with the Dobzhansky-Muller