What is the outcome of the comm"nc -l -p 2222 | nc 10.1.0.43 1234"?
A) Netcat will listen on the 10.1.0.43 interface for 1234 seconds on port 2222.
B) Netcat will listen on port 2222 and output anything received to a remote connection on 10.1.0.43 port 1234.
C) Netcat will listen for a connection from 10.1.0.43 on port 1234 and output anything received to port 2222.
D) Netcat will listen on port 2222 and then output anything received to local interface 10.1.0.43.
Correct Answer:
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