The rate constant for a second order reaction has the value of 2.5×10^-³ L·mol^-¹·s^-¹. If the initial concentration of reactant is 3.5 mol·L^-1, what will be the molar concentration of the reactant after 2.5 minutes?

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Explanation:The integrated rate law for a second order reaction is:1/[A]t - 1/[A]0 = ktwhere [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration of the reactant, k is the rate constant, and t is time.Substituting the given values into the integrated rate law, we get:1/[A]t - 1/3.5 = 2.5×10^-3 * 2.5 * 60Solving for [A]t, we get:[A]t = 0.97 mol/L

The Rate Constant for a Second Order Reaction Has the Value