110.5 grams of a biological compound is dissolved in 500 ml of water? The compound is observed to have an osmotic pressure of 97.4 Torr at 28°C. What is the molecular mass of the compound?

Question

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The correct answer is A because the osmotic pressure is directly proportional to the molar concentration of the solution. The molar concentration can be calculated using the formula:M = (P * V) / (R * T)where:M is the molar concentration in mol/LP is the osmotic pressure in TorrV is the volume of the solution in LR is the ideal gas constant (0.0821 L·atm/(mol·K))T is the temperature in KSubstituting the given values into the formula, we get:M = (97.4 Torr * 0.5 L) / (0.0821 L·atm/(mol·K) * 301 K) = 0.02 MThe molecular mass of the compound can be calculated using the formula:Molecular mass = (Mass of compound / Molar concentration) * 1000Substituting the given values into the formula, we get:Molecular mass = (110.5 g / 0.02 M) * 1000 = 42600 g/molTherefore, the molecular mass of the compound is 42600 g/mol.

1105 Grams of a Biological Compound Is Dissolved in 500