The electron affinity for sodium is 52 kJ mol^-¹ and the first ionization energy for sodium is 496 kJ mol^-¹. What is the change in energy for the following reaction?
2 Na(g) → Na⁺(g) + Na^-(g)

Question

The electron affinity for sodium is 52 kJ mol^-¹ and the first ionization energy for sodium is 496 kJ mol^-¹. What is the change in energy for the following reaction? 2 Na(g) → Na⁺(g) + Na^-(g)

Quizplus · Accepted Answer

The reaction involves ionizing one Na atom (requiring 496 kJ/mol) and adding an electron to another Na atom (releasing 52 kJ/mol). The net energy change is 496 - 52 = +444 kJ/mol.

The Electron Affinity for Sodium Is 52 KJ Mol-1 and the First

The Electron Affinity for Sodium Is 52 KJ Mol^-¹ and the First