Hydrogen has a strong emission line at 6563 Å. What is the energy difference between the energy levels in hydrogen that are involved in this transition?

Question

Quizplus · Accepted Answer

The energy difference can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626×10^-34 J·s), c is the speed of light (3×10^8 m/s), and λ is the wavelength (6563 Å = 656.3 nm = 656.3×10^-9 m). Plugging in these values gives E ≈ 3.03×10^-19 J.

Hydrogen Has a Strong Emission Line at 6563 Å