Sodium perbromate can be synthesized via the following reaction that gives off Xenon gas. $\mathrm{NaBrO}_{3}+\mathrm{XeF}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{NaBrO}_{4}+2 \mathrm{HF}+\mathrm{Xe}$ A reaction is started with 200.0g of NaBrO₃, 250.0g of XeF₂ and 100.0g of water. Assuming that the reaction goes to completion, and that all of the formed xenon gas is allowed to escape into the atmosphere, what will be the minimum mass of products and reactants remaining in the reaction vessel?

Question

Sodium perbromate can be synthesized via the following reaction that gives off Xenon gas. $\mathrm{NaBrO}_{3}+\mathrm{XeF}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{NaBrO}_{4}+2 \mathrm{HF}+\mathrm{Xe}$ A reaction is started with 200.0g of NaBrO₃, 250.0g of XeF₂ and 100.0g of water.  Assuming that the reaction goes to completion, and that all of the formed xenon gas is allowed to escape into the atmosphere, what will be the minimum mass of products and reactants remaining in the reaction vessel?

Quizplus · Accepted Answer

The Answer of  Sodium perbromate can be synthesized via the following reaction that gives off Xenon gas. $\mathrm{NaBrO}_{3}+\mathrm{XeF}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{NaBrO}_{4}+2 \mathrm{HF}+\mathrm{Xe}$ A reaction is started with 200.0g of NaBrO₃, 250.0g of XeF₂ and 100.0g of water.  Assuming that the reaction goes to completion, and that all of the formed xenon gas is allowed to escape into the atmosphere, what will be the minimum mass of products and reactants remaining in the reaction vessel?

Sodium Perbromate Can Be Synthesized Via the Following Reaction That NaBrO3+XeF2+H2O→NaBrO4+2HF+Xe\mathrm{NaBrO}_{3}+\mathrm{XeF}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{NaBrO}_{4}+2 \mathrm{HF}+\mathrm{Xe}NaBrO3​+XeF2​+H2​O→NaBrO4​+2HF+Xe

Sodium Perbromate Can Be Synthesized Via the Following Reaction That $\mathrm{NaBrO}_{3}+\mathrm{XeF}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{NaBrO}_{4}+2 \mathrm{HF}+\mathrm{Xe}$