The ionization constant of acetic acid is 1x10^-5. What is $\Delta$ G^o for the reaction? A) -6500 cal/mol B) 3250 cal/mol C) 6500 cal/mol D) 6000 cal/mol E) 1624 cal/mol

Question

Quizplus · Accepted Answer

The ionization constant (K) of acetic acid is given as $1 \times 10^{-5}$. The change in Gibbs free energy ($\Delta G^\circ$) for the reaction can be calculated using the equation $\Delta G^\circ = -RT \ln K$, where R is the gas constant (1.987 cal/mol·K) and T is the temperature in Kelvin (assumed to be 298K if not specified). Plugging in the values, $\Delta G^\circ = -1.987 \times 298 \times \ln(1 \times 10^{-5})$, which calculates to approximately 6500 cal/mol.

The Ionization Constant of Acetic Acid Is 1x10-5 Δ\DeltaΔ Go for the Reaction? A) -6500 Cal/mol B) 3250 Cal/mol

The Ionization Constant of Acetic Acid Is 1x10^-5 $\Delta$ G^o for the Reaction?
A) -6500 Cal/mol
B) 3250 Cal/mol