Ethane (C₂H₆) is a minor component of natural gas. How much oxygen (in grams) would be needed to react with 144 g ethane?
2 C₂H₆ + 7 O₂ $\rightarrow$ 4 CO₂ + 6 H₂O

Question

Ethane (C₂H₆) is a minor component of natural gas. How much oxygen (in grams) would be needed to react with 144 g ethane? 2 C₂H₆ + 7 O₂ $\rightarrow$ 4 CO₂ + 6 H₂O

Quizplus · Accepted Answer

The molar mass of ethane (C2H6) is 30 g/mol. For 144 g of ethane, the moles are 144 g / 30 g/mol = 4.8 mol. According to the balanced equation, 2 moles of C2H6 require 7 moles of O2. Therefore, 4.8 moles of C2H6 require 4.8 * (7/2) = 16.8 moles of O2. The molar mass of O2 is 32 g/mol, so the mass of O2 needed is 16.8 mol * 32 g/mol = 536 g.

Ethane (C2H6) Is a Minor Component of Natural Gas →\rightarrow→ 4 CO2 + 6 H2O A) 154 G B) 536

Ethane (C₂H₆) Is a Minor Component of Natural Gas $\rightarrow$ 4 CO₂ + 6 H₂O
A) 154 G
B) 536