How Does $\frac{4 x-16}{x^{2}+4 x-12}$ Resolve into Partial Fractions?
A) $\frac{-1}{x-2}+\frac{-5}{x+6}$ B) $\frac{1}{x-2}+\frac{-5}{x+6}$

How does $\frac{4 x-16}{x^{2}+4 x-12}$ resolve into partial fractions?

A) $\frac{-1}{x-2}+\frac{-5}{x+6}$
B) $\frac{1}{x-2}+\frac{-5}{x+6}$
C) $\frac{-1}{x-2}+\frac{5}{x+6}$
D) $\frac{1}{x-2}+\frac{5}{x+6}$