Case Study 1:
1. def railBreak(cipherText):
2. wordDict = createWordDict('wordlist.txt')
3. cipherLen = len(cipherText)
4. maxGoodSoFar = 0
5. bestGuess = "No words found in dictionary"
6. for i in range(2, cipherLen + 1):
7. words = railDecrypt(cipherText, i)
8. goodCount = 0
9. for w in words:
10. if w in wordDict:
11. goodCount = goodCount + 1
12. if goodCount maxGoodSoFar:
13. maxGoodSoFar = goodCount
14. bestGuess = " ".join(words)
15. return bestGuess
-Refer to the session in the accompanying Case Study 1. What pattern is used on lines 12-14?
A) Minmax
B) Rail break
C) Cryptology
D) Brute force

Question

Case Study 1:
1. def railBreak(cipherText):
2. wordDict = createWordDict('wordlist.txt')
3. cipherLen = len(cipherText)
4. maxGoodSoFar = 0
5. bestGuess = "No words found in dictionary"
6. for i in range(2, cipherLen + 1):
7. words = railDecrypt(cipherText, i)
8. goodCount = 0
9. for w in words:
10. if w in wordDict:
11. goodCount = goodCount + 1
12. if goodCount > maxGoodSoFar:
13. maxGoodSoFar = goodCount
14. bestGuess = " ".join(words)
15. return bestGuess
-Refer to the session in the accompanying Case Study 1. What pattern is used on lines 12-14?
A) Minmax
B) Rail break
C) Cryptology
D) Brute force

Quizplus · Accepted Answer

The pattern used on lines 12-14 is a minmax pattern. This pattern is used to find the maximum value of a variable. In this case, the variable is maxGoodSoFar. The pattern works by comparing the current value of the variable to the previous maximum value. If the current value is greater than the previous maximum value, then the current value is stored as the new maximum value.

Case Study 1: 1. Def RailBreak(cipherText)