For chlorine monofluoride, ClF, the harmonic vibrational wavenumber is 793.2 cm^-1 and the anharmonicity is 0.0125. Calculate the wavenumber of the first vibrational overtone in the infrared absorption spectrum of chlorine monofluoride.

Question

Quizplus · Accepted Answer

The wavenumber of the first vibrational overtone can be calculated using the formula for the energy levels of a vibrating diatomic molecule, considering the anharmonicity: $\nu = 2\nu_0 - 2x\nu_0$, where $\nu_0$ is the harmonic vibrational wavenumber and $x$ is the anharmonicity constant. Substituting the given values: $2 \times 793.2 - 2 \times 0.0125 \times 793.2 = 1526.9 \, \text{cm}^{-1}$.

For Chlorine Monofluoride, ClF, the Harmonic Vibrational Wavenumber Is 793