The value of the equilibrium constant for the electrochemical reaction
MnO₄^-(aq) + 2 H⁺(aq) + ½ Cl₂(g) ∏ Mn²⁺(aq) + ClO₃^-(aq) + H₂O(aq)
Is 5.88 *10^-5. What is the value of the equilibrium constant for the reverse reaction?

Question

Quizplus · Accepted Answer

The equilibrium constant for the reverse reaction is the reciprocal of the equilibrium constant for the forward reaction. Therefore, if the forward reaction has an equilibrium constant of $5.88 \times 10^{-5}$, the reverse reaction's equilibrium constant would be $1 / (5.88 \times 10^{-5})$, which is approximately $1.70 \times 10^{5}$, or as presented in scientific notation, $17.0 \times 10^{4}$.

The Value of the Equilibrium Constant for the Electrochemical Reaction