The value of the equilibrium constant for the reaction
C₂H₄(g) + H₂O(g) ∏ C₂H₅OH(g)
Is 9.920 at 423 K and 6.397 at 523 K. Determine the average value of the standard enthalpy of reaction over this temperature range.

Question

Quizplus · Accepted Answer

The correct answer is A.The average value of the standard enthalpy of reaction can be calculated using the van't Hoff equation:ln(K2/K1) = -ΔH°/R (1/T2 - 1/T1)where K1 and K2 are the equilibrium constants at temperatures T1 and T2, respectively, ΔH° is the standard enthalpy of reaction, and R is the gas constant.Substituting the given values into the equation, we get:ln(9.920/6.397) = -ΔH°/R (1/523 - 1/423)Solving for ΔH°, we get:ΔH° = -8.1 kJ mol-1

The Value of the Equilibrium Constant for the Reaction