Calculate the limiting molar conductivity of an aqueous solution of sodium phosphate, Na₃PO₄, given that the ionic conductivities of the sodium, Na⁺, and phosphate, PO₄^3-, ions are 5.01 and 24.0 mS m² mol^-¹ respectively.

Question

Quizplus · Accepted Answer

The limiting molar conductivity of an electrolyte can be calculated by summing the contributions of its ions. Sodium phosphate dissociates into three sodium ions (Na+) and one phosphate ion (PO4^3-). Therefore, the limiting molar conductivity is calculated as: 3 * (conductivity of Na+) + 1 * (conductivity of PO4^3-) = 3 * 5.01 mS m^2 mol^-1 + 1 * 24.0 mS m^2 mol^-1 = 15.03 mS m^2 mol^-1 + 24.0 mS m^2 mol^-1 = 39.03 mS m^2 mol^-1, which rounds to 39.0 mS m^2 mol^-1.

Calculate the Limiting Molar Conductivity of an Aqueous Solution of Sodium