Use the following data to determine the standard enthalpy of reaction at 298 K for the addition of hydrogen chloride, HCl, to ethene, C₂H₄
C₂H₄(g) + HCl(g) $\rightarrow$ C₂H₅Cl(g)
$\begin{array}{lc}& \Delta \$ \mathrm{H}^{\circ}(298 \mathrm{~K}) / \mathrm{kJ} \mathrm{mol}^{-1} \\\mathrm{C}_{2} \mathrm{H}_{4} \\& +52.2 \\\mathrm{HCl} \\& -92.3 \\\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl} \\ & -109.8\end{array}$

Question

Use the following data to determine the standard enthalpy of reaction at 298 K for the addition of hydrogen chloride, HCl, to ethene, C₂H₄
C₂H₄(g) + HCl(g)

\rightarrow

C₂H₅Cl(g)

\begin{array}{lc}& \Delta \$ \mathrm{H}^{\circ}(298 \mathrm{~K}) / \mathrm{kJ} \mathrm{mol}^{-1} \\\mathrm{C}_{2} \mathrm{H}_{4} \\& +52.2 \\\mathrm{HCl} \\& -92.3 \\\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl} \\ & -109.8\end{array}

Quizplus · Accepted Answer

The standard enthalpy of reaction is calculated using the formula: ΔH° = ΣΔH°(products) - ΣΔH°(reactants). For this reaction: ΔH° = [-109.8] - [52.2 + (-92.3)] = -109.8 - (-40.1) = -69.7 kJ mol⁻¹.

Use the Following Data to Determine the Standard Enthalpy of Reaction