In the reaction HA ⇌ H⁺ + A^-, what is the value of K if [HA] = 0.200 M and [A^-] = [H⁺] = 0.020 M?

Name: In the reaction HA ⇌ H + + A - , what is the value of K if [HA] = 0.200 M and [A - ] = [H + ] = 0.020 M?
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Quizplus · Accepted Answer

The equilibrium constant $K$ for the reaction $HA \rightleftharpoons HS^+ + A^-$ is given by $K = \frac{[HS^+][A^-]}{[HA]}$. Substituting the given concentrations, $K = \frac{(0.020)(0.020)}{0.200} = \frac{0.0004}{0.200} = 0.002$.

In the Reaction HA ⇌ H+ + A-, What Is

In the Reaction HA ⇌ H⁺ + A^-, What Is