In the following reaction: HCl ⇌ H⁺ + Cl^- , what is the pH value if [HCl] = 0.200 M and K = 1 × 10^-9?

Question

Quizplus · Accepted Answer

The pH value can be calculated using the equation pH = -log[H+]. The equilibrium constant for the reaction is K = [H+][Cl-]/[HCl] = 1 × 10-9. Substituting the given values into this equation, we get [H+] = 1 × 10-9/[Cl-] = 1 × 10-9/0.200 M = 5 × 10-9 M. Therefore, the pH value is pH = -log(5 × 10-9) = 4.85.

In the Following Reaction: HCl ⇌ H+ + Cl-

In the Following Reaction: HCl ⇌ H⁺ + Cl^-