In the following reaction: HA ⇌ H⁺ + A^- , what will the pH value be if [HA] = 0.150 M and K = 5.2 × 10^-9?

Question

Quizplus · Accepted Answer

The pH is calculated using the formula pH = -log[H+]. For weak acids, [H+] can be approximated using the formula [H+] = √(K * [HA]). Substituting the given values, [H+] = √(5.2 × 10^-9 * 0.150) = √(7.8 × 10^-10) ≈ 2.79 × 10^-5. Therefore, pH = -log(2.79 × 10^-5) ≈ 4.55.

In the Following Reaction: HA ⇌ H+ + A-

In the Following Reaction: HA ⇌ H⁺ + A^-