In the equilibrium reaction HAc ⇌ H⁺ + Ac^-, what is the pH of the solution if [HAc] = 0.420 M and K = 4.8 × 10^-8?

Name: In the equilibrium reaction HAc ⇌ H + + Ac - , what is the pH of the solution if [HAc] = 0.420 M and K = 4.8 × 10 -8 ?
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Quizplus · Accepted Answer

The pH of the solution can be calculated using the formula for the dissociation of a weak acid: pH = -log[H+]. For acetic acid, [H+] = √(K * [HAc]) = √(4.8 × 10^-8 * 0.420) ≈ 1.41 × 10^-4. Therefore, pH = -log(1.41 × 10^-4) ≈ 3.85.

In the Equilibrium Reaction HAc ⇌ H+ + Ac-, What

In the Equilibrium Reaction HAc ⇌ H⁺ + Ac^-, What