5.00 L of chlorine gas is at 15°C. What temperature will the gas have when the volume changes to 12.5 L?

Question

Quizplus · Accepted Answer

Using Charles's Law (V1/T1 = V2/T2), convert temperatures to Kelvin: T1 = 15°C + 273 = 288K. V1 = 5.00 L, V2 = 12.5 L. Solve for T2: T2 = (V2/V1) * T1 = (12.5/5.00) * 288K = 720K. Convert back to Celsius: 720K - 273 = 447°C. None of the options match, indicating a possible error in the choices.

500 L of Chlorine Gas Is at 15°C