If 78.0 g of potassium are consumed to make KCl according to the equation 2 K + Cl₂ → 2 KCl, how much product can form?

Question

Quizplus · Accepted Answer

The reaction 2 K + Cl2 → 2 KCl shows that 2 moles of potassium react with 1 mole of chlorine to produce 2 moles of KCl. The molar mass of potassium (K) is approximately 39.1 g/mol, so 78.0 g of potassium is about 2 moles (78.0 g / 39.1 g/mol). According to the stoichiometry of the reaction, these 2 moles of potassium will produce 2 moles of KCl. The molar mass of KCl is approximately 74.55 g/mol (39.1 g/mol for K + 35.45 g/mol for Cl), so 2 moles of KCl have a mass of about 149 g (2 moles * 74.55 g/mol).

If 780 G of Potassium Are Consumed to Make KCl According