When calcium carbonate decomposes, according to the equation CaCO₃ → CaO + CO₂, how many grams of CO₂ are produced from the decomposition of 520.0 g of CaCO₃?

Question

Quizplus · Accepted Answer

First, calculate the molar mass of CaCO3 (40.08 for Ca, 12.01 for C, and 16.00 for each O, totaling 100.09 g/mol) and CO2 (12.01 for C and 32.00 for O, totaling 44.01 g/mol). Given 520.0 g of CaCO3, divide by its molar mass to find moles of CaCO3, which equals 5.20 moles (520.0 g / 100.09 g/mol). The reaction shows a 1:1 mole ratio between CaCO3 and CO2, so 5.20 moles of CO2 are produced. Multiply the moles of CO2 by its molar mass (5.20 moles * 44.01 g/mol) to get 228.85 g of CO2, which rounds to 228.8 g.

When Calcium Carbonate Decomposes, According to the Equation CaCO3 →

When Calcium Carbonate Decomposes, According to the Equation CaCO₃ →