If 118.0 g of potassium are reacted completely with excess chlorine, according to the equation 2 K + Cl₂ → 2 KCl, how much potassium chloride could form?

Question

Quizplus · Accepted Answer

First, we calculate the molar mass of potassium (K), which is approximately 39.1 g/mol. Therefore, 118.0 g of potassium is equivalent to 118.0 g / 39.1 g/mol = 3.02 mol. According to the balanced chemical equation, 2 moles of potassium react with chlorine to produce 2 moles of potassium chloride (KCl). Thus, 3.02 moles of potassium will produce 3.02 moles of KCl. The molar mass of KCl is approximately 74.55 g/mol (39.1 g/mol for K + 35.45 g/mol for Cl). Therefore, the mass of KCl produced is 3.02 moles * 74.55 g/mol = 225.4 g.

If 1180 G of Potassium Are Reacted Completely with Excess Chlorine