Consider a situation in which Jamal measures the resting heart rate of 16 individuals from a population that he thinks (based on published reports) has an average resting heart rate of 72 beats per minute. His sample has a mean of 75.2 with a standard deviation of 6.2 cm. If he conducts a one-sample t-test of his data, what t-value would he obtain?

Question

Quizplus · Accepted Answer

The t-value is calculated using the formula: $ t = \frac{\bar{x} - \mu}{(s / \sqrt{n})} $, where $\bar{x}$ is the sample mean, $\mu$ is the population mean, $s$ is the sample standard deviation, and $n$ is the sample size. Plugging in the given values: $ t = \frac{75.2 - 72}{(6.2 / \sqrt{16})} = \frac{3.2}{(6.2 / 4)} = \frac{3.2}{1.55} = 2.065 $.

Consider a Situation in Which Jamal Measures the Resting Heart