The equation for a normal distribution with a mean of 30 and a variance of 20 is
$f(x)=\frac{1}{\sqrt{40 \pi}} e^{\frac{-(x-30)^{2}}{40}}$

Name: The equation for a normal distribution with a mean of 30 and a variance of 20 is $f(x)=\frac{1}{\sqrt{40 \pi}} e^{\frac{-(x-30)^{2}}{40}}$
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Question

The equation for a normal distribution with a mean of 30 and a variance of 20 is
 $f(x)=\frac{1}{\sqrt{40 \pi}} e^{\frac{-(x-30)^{2}}{40}}$

Quizplus · Accepted Answer

The equation given is the probability density function for a normal distribution with mean (μ) of 30 and variance (σ²) of 20, where the standard deviation (σ) is the square root of 20.

The Equation for a Normal Distribution with a Mean of 30