The value of the definite integral $\int _ { - 4 } ^ { 6 } \frac { 1 } { e } d x$ is

A) $\frac { 2 } { e }$
B) $\frac { 4 } { e }$
C) $\frac { 6 } { e }$
D) $\frac { 8 } { e }$
E) $\frac { 10 } { e }$

Question

The value of the definite integral $\int _ { - 4 } ^ { 6 } \frac { 1 } { e } d x$ is

A) $\frac { 2 } { e }$
B) $\frac { 4 } { e }$
C) $\frac { 6 } { e }$
D) $\frac { 8 } { e }$
E) $\frac { 10 } { e }$

Quizplus · Accepted Answer

The integral of a constant $ \frac{1}{e} $ over the interval from -4 to 6 is equal to the constant times the length of the interval. The length of the interval from -4 to 6 is 10, so the value of the integral is $ \frac{10}{e} $.

The Value of the Definite Integral ∫−461edx\int _ { - 4 } ^ { 6 } \frac { 1 } { e } d x∫−46​e1​dx

The Value of the Definite Integral $\int _ { - 4 } ^ { 6 } \frac { 1 } { e } d x$