What is the percentile rank of the score 610 in a unit normal distribution that has a population mean of 500 and standard deviation of 100?

Question

Quizplus · Accepted Answer

The percentile rank of a score in a normal distribution can be found by converting the score to a z-score and then finding the corresponding percentile. The z-score is calculated as (score - mean) / standard deviation. For a score of 610, the z-score is (610 - 500) / 100 = 1.1. Looking up 1.1 on a standard normal distribution table or using a calculator, we find that it corresponds to a percentile rank of approximately 87.

What Is the Percentile Rank of the Score 610 in a Unit