Assuming independent assortment for all gene pairs,what is the probability that the following parents,AABbCc × AaBbCc,will produce an AaBbCc offspring?

Question

Quizplus · Accepted Answer

The probability of each parent passing on the desired allele for each gene is 1/2. Since there are three independent gene pairs involved, the probability of all three being passed on correctly is (1/2) × (1/2) × (1/2) = 1/8. Thus, the probability of producing an AaBbCc offspring is 1/8.

Assuming Independent Assortment for All Gene Pairs,what Is the Probability