What will the following code display? String input = "99#7";
Int number;
Try
{
Number = Integer.parseInt(input);
}
Catch(NumberFormatException ex)
{
Number = 0;
}
Catch(RuntimeException ex)
{
Number = 1;
}
Catch(Exception ex)
{
Number = -1;
}
System.out.println(number);
A) -1
B) 0
C) 1
D) 99

Question

Quizplus · Accepted Answer

The code will display 0 because `Integer.parseInt(input)` will throw a `NumberFormatException` when trying to parse "99#7" as an integer, which is caught by the corresponding catch block, setting `number` to 0.

What Will the Following Code Display? String Input = "99#7";