Imagine a population where A = .2 and a = .8. Assuming random mating, what is the frequency of each genotype among the zygotes of the next generation?
A) AA = .2, Aa = 0, and aa = .8
B) AA = .40, Aa = .16, and aa = .44
C) AA = .04, Aa = .32, and aa = .64
D) AA = .40, Aa = .30, and aa = .60

Question

Quizplus · Accepted Answer

The genotype frequencies can be calculated using the Hardy-Weinberg principle: p^2 for AA, 2pq for Aa, and q^2 for aa. Here, p = 0.2 and q = 0.8, so AA = 0.2^2 = 0.04, Aa = 2(0.2)(0.8) = 0.32, and aa = 0.8^2 = 0.64.

Imagine a Population Where a =